Integrand size = 23, antiderivative size = 146 \[ \int \frac {x^2 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^{3/2}} \, dx=\frac {20 b d n \sqrt {d+e x}}{3 e^3}-\frac {4 b n (d+e x)^{3/2}}{9 e^3}-\frac {32 b d^{3/2} n \text {arctanh}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{3 e^3}-\frac {2 d^2 \left (a+b \log \left (c x^n\right )\right )}{e^3 \sqrt {d+e x}}-\frac {4 d \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^3}+\frac {2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3} \]
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Time = 0.11 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.261, Rules used = {45, 2392, 12, 911, 1167, 214} \[ \int \frac {x^2 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^{3/2}} \, dx=-\frac {2 d^2 \left (a+b \log \left (c x^n\right )\right )}{e^3 \sqrt {d+e x}}-\frac {4 d \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^3}+\frac {2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac {32 b d^{3/2} n \text {arctanh}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{3 e^3}+\frac {20 b d n \sqrt {d+e x}}{3 e^3}-\frac {4 b n (d+e x)^{3/2}}{9 e^3} \]
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Rule 12
Rule 45
Rule 214
Rule 911
Rule 1167
Rule 2392
Rubi steps \begin{align*} \text {integral}& = -\frac {2 d^2 \left (a+b \log \left (c x^n\right )\right )}{e^3 \sqrt {d+e x}}-\frac {4 d \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^3}+\frac {2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-(b n) \int \frac {2 \left (-8 d^2-4 d e x+e^2 x^2\right )}{3 e^3 x \sqrt {d+e x}} \, dx \\ & = -\frac {2 d^2 \left (a+b \log \left (c x^n\right )\right )}{e^3 \sqrt {d+e x}}-\frac {4 d \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^3}+\frac {2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac {(2 b n) \int \frac {-8 d^2-4 d e x+e^2 x^2}{x \sqrt {d+e x}} \, dx}{3 e^3} \\ & = -\frac {2 d^2 \left (a+b \log \left (c x^n\right )\right )}{e^3 \sqrt {d+e x}}-\frac {4 d \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^3}+\frac {2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac {(4 b n) \text {Subst}\left (\int \frac {-3 d^2-6 d x^2+x^4}{-\frac {d}{e}+\frac {x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{3 e^4} \\ & = -\frac {2 d^2 \left (a+b \log \left (c x^n\right )\right )}{e^3 \sqrt {d+e x}}-\frac {4 d \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^3}+\frac {2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}-\frac {(4 b n) \text {Subst}\left (\int \left (-5 d e+e x^2-\frac {8 d^2}{-\frac {d}{e}+\frac {x^2}{e}}\right ) \, dx,x,\sqrt {d+e x}\right )}{3 e^4} \\ & = \frac {20 b d n \sqrt {d+e x}}{3 e^3}-\frac {4 b n (d+e x)^{3/2}}{9 e^3}-\frac {2 d^2 \left (a+b \log \left (c x^n\right )\right )}{e^3 \sqrt {d+e x}}-\frac {4 d \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^3}+\frac {2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3}+\frac {\left (32 b d^2 n\right ) \text {Subst}\left (\int \frac {1}{-\frac {d}{e}+\frac {x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{3 e^4} \\ & = \frac {20 b d n \sqrt {d+e x}}{3 e^3}-\frac {4 b n (d+e x)^{3/2}}{9 e^3}-\frac {32 b d^{3/2} n \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{3 e^3}-\frac {2 d^2 \left (a+b \log \left (c x^n\right )\right )}{e^3 \sqrt {d+e x}}-\frac {4 d \sqrt {d+e x} \left (a+b \log \left (c x^n\right )\right )}{e^3}+\frac {2 (d+e x)^{3/2} \left (a+b \log \left (c x^n\right )\right )}{3 e^3} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 124, normalized size of antiderivative = 0.85 \[ \int \frac {x^2 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^{3/2}} \, dx=\frac {-48 a d^2+56 b d^2 n-24 a d e x+52 b d e n x+6 a e^2 x^2-4 b e^2 n x^2-96 b d^{3/2} n \sqrt {d+e x} \text {arctanh}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )-6 b \left (8 d^2+4 d e x-e^2 x^2\right ) \log \left (c x^n\right )}{9 e^3 \sqrt {d+e x}} \]
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\[\int \frac {x^{2} \left (a +b \ln \left (c \,x^{n}\right )\right )}{\left (e x +d \right )^{\frac {3}{2}}}d x\]
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Time = 0.32 (sec) , antiderivative size = 330, normalized size of antiderivative = 2.26 \[ \int \frac {x^2 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^{3/2}} \, dx=\left [\frac {2 \, {\left (24 \, {\left (b d e n x + b d^{2} n\right )} \sqrt {d} \log \left (\frac {e x - 2 \, \sqrt {e x + d} \sqrt {d} + 2 \, d}{x}\right ) + {\left (28 \, b d^{2} n - 24 \, a d^{2} - {\left (2 \, b e^{2} n - 3 \, a e^{2}\right )} x^{2} + 2 \, {\left (13 \, b d e n - 6 \, a d e\right )} x + 3 \, {\left (b e^{2} x^{2} - 4 \, b d e x - 8 \, b d^{2}\right )} \log \left (c\right ) + 3 \, {\left (b e^{2} n x^{2} - 4 \, b d e n x - 8 \, b d^{2} n\right )} \log \left (x\right )\right )} \sqrt {e x + d}\right )}}{9 \, {\left (e^{4} x + d e^{3}\right )}}, \frac {2 \, {\left (48 \, {\left (b d e n x + b d^{2} n\right )} \sqrt {-d} \arctan \left (\frac {\sqrt {e x + d} \sqrt {-d}}{d}\right ) + {\left (28 \, b d^{2} n - 24 \, a d^{2} - {\left (2 \, b e^{2} n - 3 \, a e^{2}\right )} x^{2} + 2 \, {\left (13 \, b d e n - 6 \, a d e\right )} x + 3 \, {\left (b e^{2} x^{2} - 4 \, b d e x - 8 \, b d^{2}\right )} \log \left (c\right ) + 3 \, {\left (b e^{2} n x^{2} - 4 \, b d e n x - 8 \, b d^{2} n\right )} \log \left (x\right )\right )} \sqrt {e x + d}\right )}}{9 \, {\left (e^{4} x + d e^{3}\right )}}\right ] \]
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Time = 135.75 (sec) , antiderivative size = 308, normalized size of antiderivative = 2.11 \[ \int \frac {x^2 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^{3/2}} \, dx=a \left (\begin {cases} - \frac {2 d^{2}}{e^{3} \sqrt {d + e x}} - \frac {4 d \sqrt {d + e x}}{e^{3}} + \frac {2 \left (d + e x\right )^{\frac {3}{2}}}{3 e^{3}} & \text {for}\: e \neq 0 \\\frac {x^{3}}{3 d^{\frac {3}{2}}} & \text {otherwise} \end {cases}\right ) - b n \left (\begin {cases} \frac {16 d^{\frac {3}{2}} \sqrt {1 + \frac {e x}{d}}}{9 e^{3}} + \frac {2 d^{\frac {3}{2}} \log {\left (\frac {e x}{d} \right )}}{3 e^{3}} - \frac {4 d^{\frac {3}{2}} \log {\left (\sqrt {1 + \frac {e x}{d}} + 1 \right )}}{3 e^{3}} + \frac {12 d^{\frac {3}{2}} \operatorname {asinh}{\left (\frac {\sqrt {d}}{\sqrt {e} \sqrt {x}} \right )}}{e^{3}} + \frac {4 \sqrt {d} x \sqrt {1 + \frac {e x}{d}}}{9 e^{2}} - \frac {8 d^{2}}{e^{\frac {7}{2}} \sqrt {x} \sqrt {\frac {d}{e x} + 1}} - \frac {8 d \sqrt {x}}{e^{\frac {5}{2}} \sqrt {\frac {d}{e x} + 1}} & \text {for}\: e > -\infty \wedge e < \infty \wedge e \neq 0 \\\frac {x^{3}}{9 d^{\frac {3}{2}}} & \text {otherwise} \end {cases}\right ) + b \left (\begin {cases} - \frac {2 d^{2}}{e^{3} \sqrt {d + e x}} - \frac {4 d \sqrt {d + e x}}{e^{3}} + \frac {2 \left (d + e x\right )^{\frac {3}{2}}}{3 e^{3}} & \text {for}\: e \neq 0 \\\frac {x^{3}}{3 d^{\frac {3}{2}}} & \text {otherwise} \end {cases}\right ) \log {\left (c x^{n} \right )} \]
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Time = 0.27 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.08 \[ \int \frac {x^2 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^{3/2}} \, dx=\frac {4}{9} \, b n {\left (\frac {12 \, d^{\frac {3}{2}} \log \left (\frac {\sqrt {e x + d} - \sqrt {d}}{\sqrt {e x + d} + \sqrt {d}}\right )}{e^{3}} - \frac {{\left (e x + d\right )}^{\frac {3}{2}} - 15 \, \sqrt {e x + d} d}{e^{3}}\right )} + \frac {2}{3} \, b {\left (\frac {{\left (e x + d\right )}^{\frac {3}{2}}}{e^{3}} - \frac {6 \, \sqrt {e x + d} d}{e^{3}} - \frac {3 \, d^{2}}{\sqrt {e x + d} e^{3}}\right )} \log \left (c x^{n}\right ) + \frac {2}{3} \, a {\left (\frac {{\left (e x + d\right )}^{\frac {3}{2}}}{e^{3}} - \frac {6 \, \sqrt {e x + d} d}{e^{3}} - \frac {3 \, d^{2}}{\sqrt {e x + d} e^{3}}\right )} \]
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\[ \int \frac {x^2 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^{3/2}} \, dx=\int { \frac {{\left (b \log \left (c x^{n}\right ) + a\right )} x^{2}}{{\left (e x + d\right )}^{\frac {3}{2}}} \,d x } \]
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Timed out. \[ \int \frac {x^2 \left (a+b \log \left (c x^n\right )\right )}{(d+e x)^{3/2}} \, dx=\int \frac {x^2\,\left (a+b\,\ln \left (c\,x^n\right )\right )}{{\left (d+e\,x\right )}^{3/2}} \,d x \]
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